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Full-Load Current of a 200 kVA Transformer at 400, 415 and 11 000 V

The full-load (rated) current of a three-phase transformer follows from its rating and the line-to-line voltage of each winding: I = S / (√3 × V). For 200 kVA that is 288.7 A on a 400 V secondary and 10.5 A on an 11 kV primary.

Ratings from 200 to 630 kVA are common in distribution substations for residential areas and in commercial buildings; at 400 V a 200 kVA unit delivers 288.7 A at full load.

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Rated current of a 200 kVA transformer

Worked example

200 kVA, 11 kV / 400 V, three-phase:

I_LV = 200 × 1000 / (1.73205 × 400) = 288.68 A I_HV = 200 × 1000 / (1.73205 × 11 000) = 10.5 A Check: I_LV / I_HV = 11 000 / 400 = 27.5

The currents on the two sides are in the inverse ratio of the voltages, because the same kVA passes through the transformer (losses neglected).

Single-phase equivalent

A single-phase transformer of the same 200 kVA at 230 V would carry 200 × 1000 / 230 = 869.6 A. In the three-phase unit each phase winding handles one third of the rating, 66.67 kVA; on a star-connected 400 V secondary the phase voltage is 231 V and the phase current equals the line current in the table.

What the full-load current is used for

  • Cables or busbar trunking from the LV terminals to the main switchboard are sized for at least 288.7 A after applying the correction factors of their installation; the cable size calculator handles the ambient and grouping factors.
  • The LV main breaker is chosen with a rated current at or above the full-load current; the smallest of the common MCCB ratings listed on this site that reaches 288.7 A is 320 A. The final choice also depends on the cable, discrimination and the ambient temperature inside the switchboard.
  • Current transformers for metering and protection have standard primary ratings in IEC 61869-2 (10, 12.5, 15, 20, 25, 30, 40, 50, 60 and 75 A and their decimal multiples). A common practice is to take the first one at or above the full-load current, here 300 A on the 400 V side; the metering accuracy class and the protection requirements decide the final ratio.
  • On the primary side, HV fuses and relay settings start from the primary full-load current but must also ride through the magnetising inrush when the transformer is energised; they are selected from the fuse or relay maker's tables.
  • Measured current divided by full-load current gives the transformer loading; the transformer loading calculator adds losses and efficiency.

Example: fault current at the LV terminals

Assume, for illustration only, an impedance voltage of uk = 4 %. IEC 60076-5 lists minimum short-circuit impedances by rating, and the actual value is on the nameplate; it governs. With an infinite upstream network:

Isc ≈ I_LV / (uk / 100) = 288.68 / 0.04 = 7.22 kA

A real source impedance lowers this figure and the voltage factor of IEC 60909-0 raises it slightly; the short-circuit calculator takes both into account and continues to the end of a cable. Transformer Short-Circuit Current Calculator

Run your own numbers

Both calculators open preset to 200 kVA at 400 V. Add the actual load and the loss figures to see loading and efficiency, or work out the current of any other load.